18-2k^2=16k

Solution for 18-2k^2=16k equation:

18-2k^2=16k

We move all terms to the left:

18-2k^2-(16k)=0

a = -2; b = -16; c = +18;
Δ = b2-4ac
Δ = -162-4·(-2)·18
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20}{2*-2}=\frac{-4}{-4}
=1
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20}{2*-2}=\frac{36}{-4}
=-9
$